Bzoj 2721
Web有(x+y)n!=xy。套路地提出x和y的gcd,设为d,令ad=x,bd=y。则有(a+b)n!=abd。此时d已是和a、b无关的量。由a与b互质,得a+b与ab互质,于是将a+b除过来得n!=abd/(a+b)。 Web题意: 解法: 1 x + 1 y =
Bzoj 2721
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